Answer Base

It is for a biochemistry assignment, spent an hour or so researching, and could not work it out! i didnt do a-level chemistry, but this is part of my sports science degree

Here is my best shot.hac + naoh ---_ naac + hohyou want 0.1 m naac so that mean 0.1 moles na and 0.1 moles ac per liter. since you are making 500 mls, or 1/2 liter, you need 0.05 moles of each.from 0.2m naoh will come the 0.05 moles of na, so0.2 moles/l (x liters) = 0.05 moles of na; x = 0.25 litersfrom 0.4m hac will come the 0.05 moles of ac, so0.4moles/l (x liters) = 0.05 moles of ac; x = 0.125 litersso, if you take 250 mls of 0.2m naoh and add 125 mls of 0.4m hac, and then bring the final volume to 500 mls by adding 125 mls water, that should do it. i cannot tell you what the ph will be, but it could actually be calculated using the hederson hasselbalch equation